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A cinema hall has a volume of 7500 m3. What should be the total absorption in the hall if the reverberation time of 1.5 seconds is to be maintained?


1. 200 Sabin-m2
2. 167 Sabin-m2
3. 835 Sabin-m2
4. 535 Sabin-m2

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Correct Answer - Option 3 : 835 Sabin-m2

\(R{T_{60}} = \frac{{0.167V}}{{Sa}}\)

Where RT60 is the reverberation time (to drop 60 dB), V is the volume of the room (m3), S is the total surface area of the room (m2), a is the average absorption coefficient of room surface (Sabine/m2) and Sa is the total absorption in sabines.

\(T = \frac{{0.167V}}{{Sa}}\)

T = 1.5 seconds

V = 7500 m3

Sa = 835 Sabin-m2

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