Correct Answer - Option 1 : 42.8%
\(h = 8\frac{{fL{Q^2}}}{{g{\pi^2}{D^5}}}\)
\(\frac{{Q_1^2}}{{D_1^5}} = \frac{{Q_2^2}}{{D_2^5}}\) (For same head difference)
\(\frac{{{Q_2}}}{{{Q_1}}} = {\left( {0.8} \right)^{\frac{5}{2}}}\)
Q2 = 57.2% of Q1
Reduction is discharge = 42.8%