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The gradient for a B.G railway line such that the grade resistance together with curve resistance due a 4° curve which will be equivalent to a simple ruling gradient of 1 in 150 is
1. 1 : 180
2. 1 : 200
3. 1 : 300
4. 1 : 400

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Correct Answer - Option 2 : 1 : 200

Grade resistance + Curve resistance = Ruling gradient resistance

\(\frac{W}{S} + 0.0004 \times 4 \times W = \frac{W}{{150}}\)

Solving this equation we get gradient= 1:200

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