Question

According to Stoke’s Law for settling velocity of small particles and viscous flow.
1. \({v_s} = \frac{g}{{18}}.\left( {G - 1} \right).\frac{d}{v}\)
2. \({v_s} = \frac{g}{{18}}.\left( {G - 1} \right).\frac{{{d^2}}}{v}\)
3. \({v_s} = \frac{{18}}{g}.\left( {G - 1} \right).\frac{{{d^2}}}{v}\)
4. \({v_s} = \frac{g}{{18}}.\left( {G + 1} \right).\frac{{{d^2}}}{v}\)

Answer 1

Correct Answer - Option 2 : \({v_s} = \frac{g}{{18}}.\left( {G - 1} \right).\frac{{{d^2}}}{v}\)

This is applicable for particle size less than 0.01mm.