Question

While measuring the velocity of air (ρ = 1.2 kg/m³), the difference in the stagnation and static pressure of a Pitot static tube was found to be 380 Pa. The velocity at that location is
1. 24.03 m/s
2. 4.02 m/s
3. 17.8 m/s
4. 25.17 m/s

Answer 1

Correct Answer - Option 4 : 25.17 m/s
\(\begin{array}{l} \frac{{{v^2}}}{{2g}} = \frac{P_{stag}-P_{static}}{{\rho g}}\\ \therefore v = \sqrt {\frac{{2(P_{stag}-P_{static}})}{\rho }} = \sqrt {\frac{{2 \times 380}}{{1.2}}} = 25.17\frac{m}{s} \end{array}\)