Correct Answer - Option 2 :
\(\left( {{\rm{x\;}} + {\rm{\;y\;}} + {\rm{\;z}}} \right)\left( {{\rm{x\;}} + {\rm{\;\bar y}} + {\rm{\;\bar z}}} \right)\left( {{\rm{\bar x}} + {\rm{\;y\;}} + {\rm{\;z}}} \right)\)
Concept:
A Boolean expression consisting purely of Minterms (product terms) is said to be in the canonical sum of products form.
A Boolean expression consisting purely of Maxterms (sum terms) is said to be in the canonical product of sums form.
a) (A + B)(C + D) – POS form
b) (A)B(C + D) – POS form
c) AB + CD – SOP form
Calculation:
Given logic, expression is minterm expression.
\({\rm{F\;}}\left( {{\rm{x}},{\rm{\;y}},{\rm{\;z}}} \right){\rm{\;}} = {\rm{\Sigma m}}\left( {1,2,5,6,7} \right){\rm{\;}} \)
The max term expression will be formed by the terms which are not present in the min-term expression.
By converting the above min-term expression into max term expression,
\({\rm{F\;}}\left( {{\rm{x}},{\rm{\;y}},{\rm{\;z}}} \right){\rm{\;}} = {\rm{\Sigma m}}\left( {1,2,5,6,7} \right){\rm{\;}} = {\rm{\;\pi M\;}}\left( {0,3,4} \right)\)
We get
\(F= {\rm{\;}}\left( {{\rm{x\;}} + {\rm{\;y\;}} + {\rm{\;z}}} \right)\left( {{\rm{x\;}} + {\rm{\;\bar y}} + {\rm{\;\bar z}}} \right)\left( {{\rm{\bar x}} + {\rm{\;y\;}} + {\rm{\;z}}} \right)\)