# A 16 kb (= 16, 384 bit) memory array is designed as a square with an aspect ratio of one (number of rows is equal to the number of columns). The minim

76 views

closed
A 16 kb (= 16, 384 bit) memory array is designed as a square with an aspect ratio of one (number of rows is equal to the number of columns). The minimum number of address lines needed for the row decoder is __________.

by (37.3k points)
selected

The size of a memory register is given by ${\rm{M}} \times {\rm{N}}$ where ${\rm{M}}$ is the number of rows and ${\rm{N}}$ is the number of columns. Now, the given memory array is in the size of a square, i.e, the number of rows is equal to the number of columns. Thus, ${\rm{M}} = {\rm{N}}$. So, we have ${{\rm{M}}^2} = 16384$.

$\Rightarrow {\rm{M}} = 128$

Now, the rows are fetched by the address lines and all the registers of a particular row are handled by data lines. Now, for a register with 128 flip flops can be handled by ${\log _2}128 = 7$ data lines. Similarly, the number of address lines required by the row decoder is also 7.