Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
458 views
in Electronics by (115k points)
closed by
For a unit step input a system with forward path transfer function G(s) = 20 / s2 and feedback path transfer function H(s) = (s + 5), has a steady state output of
1. 2
2. 0.5
3. 0.2
4. 1

1 Answer

0 votes
by (152k points)
selected by
 
Best answer
Correct Answer - Option 3 : 0.2

Concept:

Final value theorem:

  • A final value theorem allows the time domain behavior to be directly calculated by taking a limit of a frequency domain expression
  • Final value theorem states that the final value of a system can be calculated by

\(f\left( \infty \right) = \mathop {\lim }\limits_{s \to 0} sF\left( s \right)\)

 Where F(s) is the Laplace transform of the function.

  • For the final value theorem to be applicable system should be stable in steady-state and for that real part of poles should lie in the left side of s plane.

 

Initial value theorem:

\(C\left( 0 \right) = \mathop {\lim }\limits_{t \to 0} c\left( t \right) = \mathop {\lim }\limits_{s \to \infty } sC\left( s \right)\)

It is applicable only when the number of poles of C(s) is more than the number of zeros of C(s).

Calculation:

Transfer function will be

\(\begin{array}{l} \frac{{C\left( s \right)}}{{R\left( s \right)}} = \frac{{G\left( s \right)}}{{1 + G\left( s \right)H\left( s \right)}}\\ = \frac{{20}}{{{s^2} + 20s + 100}} \end{array}\)

Apply final value theorem,

\(\mathop {\lim }\limits_{s \to 0} sC\left( s \right) = \mathop {\lim }\limits_{s \to 0} s\frac{{20}}{{{s^2} + 20s + 100}} \times \frac{1}{s} = 0.2\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...