Concept:
In case of thin cylinder,
Hoop Stress, \(\sigma_h = \frac{{Pd}}{{2t}}\)
Longitudinal stress, \(\sigma_l = \frac{{Pd}}{{4t}}\)
The maximum stress in case of the thin cylinder is
\(\sigma = \sigma_h = \frac{{Pd}}{{2t}}\)
Calculation:
Given:
σ = 100 MPa, P = 10 MPa, d = 2r = 200 mm
\(\sigma = \frac{{Pd}}{{2t}}\)
\(100 = \frac{{10 \times 200}}{{2 \times t}}\)
⇒ t = 10 mm