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Ball bearings are rated by a manufacturer for a life of 106 revolutions. The catalogue rating of a particular bearing is 16 kN. If the design load is 2 kN, the life of the bearing will be p × 106 revolutions, where p is equal to _______

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Concept:

Life of a bearing is given by:

\({L_{10}} = {\left( {\frac{C}{W}} \right)^n}\)

where

L10 = basic life rating in million revolutions

C = dynamic load-carrying capacity

W = equivalent dynamic load

n = constant = 3 for ball bearing and \(\frac{{10}}{3}{\rm{\;}}\)for roller bearing

Calculation:

Given:

C = 16kN, W = 2kN, n = 3 (ball bearing)

Life of bearing

\({L_{10}} = {\left( {\frac{C}{W}} \right)^n} = {\left( {\frac{{16}}{2}} \right)^3} = 512\;million\;revolutions = 512 \times {10^6}\;revolutions\)

∴ p = 512

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