Explanation:
Using Bernoulli’s equation:
\(\frac{{{P_1}}}{{{ρ _g}}} + \frac{{v_1^2}}{{2g}} + {z_1} = \frac{{{p_2}}}{{ρ g}} + \frac{{v_2^2}}{{2g}} + {z_2}\)
Given that
→ P1 = 400000 Pa, P2 = 130000 Pa, Z1 = Z2 and ρ = 1000
Apply Continuity Equation:
A1V1 = A2V2
\(\frac{\pi }{4}{(80)^2}{V_1} = \frac{\pi }{4}{(40)^2}{V_2}\)
V2 = 4V1
\({\frac{{{400000} }}{{ρ g}}} + \frac{{V_1^2}}{{2g}} = { {\frac{{130}000}{{ρ g}}}} + {{\frac{{(4{V_1})^2}}{{2g}}}} \)
\(400 + \frac{{V_1^2}}{2} = 130 + \frac{{16V_1^2}}{2}\)
\(\frac{{15V_1^2}}{2} = 270\;\)
\(V_1^2 = 36\)
V1 = 6 m/s