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Velocity vector of a flow field is given as \(\vec V = 2xy\hat i - {x^2}z\hat j\). Vorticity vector at (1,1,1) is


1. \(4\hat i - \hat j\)
2. \(4\hat i - \hat k\)
3. \(\hat i - 4\hat j\)
4. \(\hat i - 4\hat k\)

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Best answer
Correct Answer - Option 4 : \(\hat i - 4\hat k\)

Concept:

\(\vec F = \left( {{x^2}y} \right)̂ i + \left( {2xz} \right)̂ j + \left( {3y{z^2}} \right)̂ k\)

\({\rm{Vorticity\;vector\;}} = {\rm{\;curl\;}}\vec F = \nabla \times \vec F\)

Calculation:

Given:

\(\vec V = 2xy\hat i - {x^2}z\hat j\)

\(\therefore {\rm{curl\;}}\vec F = \left| {\begin{array}{*{20}{c}} {̂ i}&{̂ j}&{̂ k}\\ {\frac{\partial }{{\partial x}}}&{\frac{\partial }{{\partial y}}}&{\frac{\partial }{{\partial z}}}\\ {{2x}y}&{-x^2z}&{{0}} \end{array}} \right|\)

curl F = [0 - (-x2)]î - [0 - 0]ĵ + [-2xz - 2x]k̂

curl F = x2î - (2xz + 2x)k̂ 

At point (1, 1, 1)

curl F = î - 4k̂

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