Correct Answer - Option 1 : 2
Concept:
Indicated Power for four-stroke engine is given by,
\(I.P.~=~\frac{P_mLAN}{60,000× 2}\)
where Pm = mean effective pressure in N/m2, L = stroke length in m, A = Area of cross-section of the cylinder in m2, N = rpm of the engine crankshaft
\(η_m~=~\frac{B.P.}{I.P.}\)
where ηm = mechanical efficiency, B.P. = brake power, I.P. = Indicated power
Calculation:
Given:
Volume = Area × Length = AL = 0.0259 m3 (25.9 litres)
IP = 950 kW, N = 2200 rpm, Four stroke
\(IP=\frac{P_mLAn}{60}=\frac{P_mLAN}{2×60}\)
\(950=\frac{P_m×0.0259×2200}{2×60}=2000\;kPa=2\;MPa\)