Correct Answer - Option 4 : 1.01mA

__Concept:__

Current gain β is given as:

\(\beta = \frac{\alpha }{{1 - \alpha }}\)

Collector current in terms of reverse bias saturation current is given as:

\({I_c}={β{I_B}}+{\left(1+β\right)}I_s\)

__Calculation:__

Given:

Is = 0.6μA

α=0.98

IB= 20µA

\(\beta = \frac{0.98}{{1 - 0.98}}=49\)

putting values,

\({I_c}={49\times{20μ{A}}}+{\left(50\right)}\times0.6μ{A}\)

\({I_c}=0.98{m}A+0.03{m}A=1.01mA\)