Correct Answer - Option 4 : 1.01mA
Concept:
Current gain β is given as:
\(\beta = \frac{\alpha }{{1 - \alpha }}\)
Collector current in terms of reverse bias saturation current is given as:
\({I_c}={β{I_B}}+{\left(1+β\right)}I_s\)
Calculation:
Given:
Is = 0.6μA
α=0.98
IB= 20µA
\(\beta = \frac{0.98}{{1 - 0.98}}=49\)
putting values,
\({I_c}={49\times{20μ{A}}}+{\left(50\right)}\times0.6μ{A}\)
\({I_c}=0.98{m}A+0.03{m}A=1.01mA\)