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n = 475AB is a positive integer whose tens and units digits are A and B, respectively. If n is divisible by 5, 8 and 9, then what is (10A + B) ?
1. 60
2. 20
3. 15
4. 35

1 Answer

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Correct Answer - Option 2 : 20

Given:

n = 475AB

Concept:

Divisibility test 5 = Numbers, which last with digits, 0 or 5 are always divisible by 5.

Divisibility test 8 = If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.

Divisibility test 9 = If the sum of digits of the number is divisible by 9, then the number itself is divisible by 9.

Calculation:

For 5, A = 2 and B = 0 then number is divisible by 5.

But when last three digit is 520, number is divisible by 8.

For 9: 4 + 7 + 5 + A + B = 16 + A + B, then to be divisible by 9, A + B must be 2.

We can not take A + B = 11 as then number is not divisible by 5.

Then A = 2 and B = 0

∴ 10A + B = 10 × 2 + 0 = 20

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