Question

A box contains 6 white, 2 black and 3 red balls. If a ball is drawn randomly, what is the probability that it will not be white?
1. \(\frac{5}{6}\)
2. \(\frac{5}{11}\)
3. \(\frac{6}{11}\)
4. \(\frac{6}{5}\)

Answer 1

Correct Answer - Option 2 : \(\frac{5}{11}\)

Given:

A box has 6 white, 2 black and 3 red balls. 

Formula used:

Probability = No of favorable outcomes/Total no of possible outcomes 

Calculation:

Total no of balls = 6 + 2 + 3 = 11 

∴ P(Not a white ball) = 5/11