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in Mathematics by (72.7k points)

An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times, Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5, is

(a) 1 6/81

(b) 1/81

(c) 80/81

(d) 65/81

1 Answer

+1 vote
by (69.9k points)
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Best answer

The correct option is (a) 16/81

Explanation:

Let A = getting not less than 2 and not greater than 5

⇒ A = {2, 3, 4, 5}

⇒ P(A) = 4/6

But die is rolled four times, therefore the probability in getting four throws

= (4/6)(4/6)(4/6)(4/6) = 16/81

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