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A rectangular field 50 meters long and 40 meters broad contains a rectangular lawn inside it surrounded by a gravel path of uniform width of 6 meters. Then the area of the path is:
1. 730 m2
2. 936 m2
3. 480 m2
4. 720 m2

1 Answer

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Best answer
Correct Answer - Option 2 : 936 m2

Given:

Length of rectangle = 50 m

Breadth of rectangle = 40 m

Width of path = 6 m

Formula Used:

Area of rectangle = Length × breadth

Calculation:

Length of outer rectangle = 50 m

Breadth of outer rectangle = 40 m

⇒ Area of outer rectangle = 50 × 40 = 2000 m2

Length of inner rectangle = 50 - 6 - 6 = 38 m

Breadth of inner rectangle = 40 - 6 - 6 = 28 m

⇒ Area of inner rectangle = 38 × 28 = 1064 m2

Area of path = Area of outer rectangle - Area of inner rectangle 

⇒ Area of path = 2000 - 1064 = 936 m2

∴ Area of the path is 936 sq. m

The correct option is 2 i.e. 936 sq. m

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