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In a pipe of diameter 5 cm, water is flowing at a rate of 8 cm/sec. If the dynamic viscosity of water is 1.6 × 10-2 Pa-s, what type of flow is present?
1. Laminar flow
2. Transient flow
3. Turbulent flow
4. Cannot say

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Correct Answer - Option 1 : Laminar flow

Reynold Number:

  • It is the ratio of inertia force to viscous force.
  • It determines the type of fluid flow.

The expression for Reynold's number is given as:

\(Re\ =\ \frac{ρVD}{μ}\)

Where ρ = density of the fluid, V = mean velocity, D = diameter of the pipe, and μ = dynamic viscosity of the fluid.

  • The flow is laminar if Reynold number < 2000.
  • The flow is turbulent if Reynold number > 4000.

Calculation:

Given:

D = 5 cm = 5 × 10-2 m, V = 8 cm/sec = 0.08 m/sec, μ = 1.6 × 10-2 Pa-sec, ρ = 1000 kg/m

\(Re\ =\ \frac{ρVD}{μ}\)

\(Re\ =\ \frac{1000\;\times\;0.08\;\times\;5\;\times\;10^{-2}}{1.5\times\;10^{-2}}=266.6\)

The flow is laminar as Reynold number < 2000

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