Correct Answer - Option 1 : d1 > d2
Concept:
Let consider the volume of two fluids is V1 and V2 and the masses of fluid m1 and m2 respectively.
Now
Specific Volume - It is a property of materials, defined as the number of cubic meters occupied by one kilogram of a particular substance.
So, Specific volumes for two fluids are as follows
S1 = V1 / m1 . ...........(i)
S2 = V2 / m2 .............(ii)
Using the relationship between mass density, the mass of fluid, and volumes
\(Mass\space density = {Mass \over Volume}\)
Assume the mass density of the above fluids is d1 and d2, hence
\(d_1 ={m_1 \over V_1}\space and \space d_2 ={m_2 \over V_2}\)
Then the relation between specific volume and mass density of fluids by using equations (i) and (ii)
S1 = 1 / d1 and S2 = 1 / d2
So the relation between specific volume and mass density is inversely proportional to each other.
Hence, in this question given that the specific volume of two fluids is S1 < S2 , so mass density is d1 > d2.