Correct Answer - Option 1 : d1 > d2

**Concept:**

Let consider the volume of two fluids is V_{1} and V_{2} and the masses of fluid m_{1} and m_{2} respectively.

Now

**Specific Volume - **It is a property of materials, defined as the number of cubic meters occupied by one kilogram of a particular substance.

So, Specific volumes for two fluids are as follows

S_{1} = V_{1} / m_{1} . ...........(i)

S_{2} = V_{2} / m_{2} .............(ii)

Using the relationship between mass density, the mass of fluid, and volumes

\(Mass\space density = {Mass \over Volume}\)

Assume the mass density of the above fluids is d_{1} and d_{2}, hence

\(d_1 ={m_1 \over V_1}\space and \space d_2 ={m_2 \over V_2}\)

Then the relation between specific volume and mass density of fluids by using equations (i) and (ii)

S_{1} = 1 / d_{1} and S_{2} = 1 / d_{2}

So the relation between specific volume and mass density is inversely proportional to each other.

**Hence, in this question given that the specific volume of two fluids is S**_{1} < S_{2} , so mass density is d_{1} > d_{2}.