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Calculate the gauge pressure in bar, inside a mercury ball of radium 4 mm, if the surface tension of mercury is 0.465 N/m.
1. 0.465 bar
2. 465 bar
3. 465 × 10-5 bar
4. 465 × 10-6 bar

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Correct Answer - Option 3 : 465 × 10-5 bar

Concept:

\(Intensity\;of\;Pressure = \frac{{2σ }}{R} = \frac{{4σ }}{D}\)

σ  = Surface tension

D = Diameter of droplet

1 bar = 1,00,000 Pa

1 Pa = 10-5 bar

Calculation:

Given:

D = 4 mm = 0.004 mm

σ = 0.465 N/m

\({\rm{\Delta }}P = \frac{{4 × 0.465}}{{0.004}} = 465~Pa\)

ΔP = 465  Pa  = 465 × 10-5 bar

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