Correct Answer - Option 2 : X = Y/2
Explanation:
For thin cylinder:
Longitudinal stress: \({\sigma _L} = \frac{{pd}}{{4t}}\)
Hoop stress: \({\sigma _h} = \frac{{pd}}{{2t}} = 2{\sigma _L}\) = Y
For thin spherical vessel:
For a thin spherical pressure vessel, both longitudinal and hoop stress is the same and given as
\({\sigma _h} = \frac{{pd}}{{4t}} = {\sigma _L}\) = X
From the above expressions,
\(X =\frac{pd}{4t}\) and \(Y =\frac{pd}{2t}\)
Hence, X = Y/2