Correct Answer - Option 4 : 25
If I keep 2 or 3 or 4 in a pack,
LCM of 2, 3, and 4 = 12
Then, the minimum number of sweets could be 12 + 1 = 13 so that 1 sweet left after packing.
But, if I keep 5 in a pack, I am left with none, (13 is not divisible by 5) then we have to take,
12 × 2 = 24
We have to add one so that 1 sweet left after packing in 2 or 3 or 4 groups and when in group of 5 then no sweets left. Therefore,
Total minimum sweets = 24 + 1 = 25 (25 is divisible by 5).
Hence, 25 is the correct answer.