Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
491 views
in Reasoning by (106k points)
closed by
I have a few sweets to be distributed. If I keep 2 or 3 or 4 in a pack, I am left with 1 sweet. if I keep 5 in a pack, I am left with none, What is the minimum number of sweets I have pack and distribute ?
1. 54
2. 65
3. 37
4. 25

1 Answer

0 votes
by (110k points)
selected by
 
Best answer
Correct Answer - Option 4 : 25

If I keep 2 or 3 or 4 in a pack, 

LCM of 2, 3, and 4 = 12

Then, the minimum number of sweets could be 12 + 1 = 13 so that 1 sweet left after packing.

But, if I keep 5 in a pack, I am left with none, (13 is not divisible by 5) then we have to take, 

12 × 2 = 24 

We have to add one so that 1 sweet left after packing in 2 or 3 or 4 groups and when in group of 5 then no sweets left. Therefore,

Total minimum sweets = 24 + 1 = 25 (25 is divisible by 5).

Hence, 25 is the correct answer.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...