Correct Answer - Option 1 : 4 V
Concept:
The transformation ratio in a transformer is
\(K = \frac{{{N_2}}}{{{N_1}}} = \frac{{{V_2}}}{{{V_1}}} = \frac{{{I_1}}}{{{I_2}}}\)
N2 = Secondary turns
N1 = Primary turns
V1 = Primary voltage
V2 = Secondary voltage
I1 = Primary current
I2 = Secondary current
Calculation:
Given
I2 = Secondary current = 48 A
I1 = Primary current = 12 A
V1 = Primary voltage = 16 V
\(\frac{{{V_2}}}{{{V_1}}} = \frac{{{I_1}}}{{{I_2}}} \Rightarrow \frac{V_2}{16}=\frac{12}{48}\Rightarrow V_2=4 \;V\)
The Secondary voltage is 4 V