Correct Answer - Option 2 : 0.6
Fill Factor (FF):
Fill factor (FF) is the ratio of the actual maximum obtainable power (Pmax) to the product of short circuit current (Isc) and open circuit voltage (Voc).
We have,
actual maximum obtainable power (Pmax ) = 30W
Open circuit voltage (Voc) = 10 V
short circuit current (Isc) = 5 A
From the above concept,
\(FF=\frac{P_{max}}{V_{oc}I_{sc}}\)
or, \(FF=\frac{30}{10\times 5}=\frac{3}{5}=0.6\)