Correct Answer - Option 4 : 125 W
Calculation:
Given,
V = 100 V, Rating of bulb = 100 W
Rating of the bulb : \(P = \frac{V^2}{R}\)
⇒ \(R = \frac{V^2}{P} = \frac{(100)^2}{10 } = 100 Ω\)
∴ Resistance of bulb = 100 Ω
Power consumed at 150 V
∴ \(P = \frac{V^2}{R} = \frac{150 \times 150 }{100 } = 225\;W\)
Power consumed at 100 V
\(P = \frac{V^2}{R} = \frac{100 \times 100}{100} = 100\;W\)
∵ Difference = 225 - 100 = 125 W
The difference of power consumed by a 100 W light bulb at 100 V versus at 150 V is 125 W.
