Correct Answer - Option 1 : 63765 Pa

__Concept:__

- The normal force exerted by liquid at rest on a given surface in contact is called the thrust of liquid on that surface.
- The normal force (or thrust) exerted by liquid at rest per unit area of the surface in contact with it, is called pressure of liquid or hydrostatic pressure.
- If P is the pressure for a point at depth h below the surface of a liquid of density ρ.

Hydrostatic pressure P is given by P = ρgh

__Calculation__:

__Given:__

Height (h) = 5 m, density of water (ρ) = 1.3 × 103 kg/m3

The pressure at a depth of 5 m is:

⇒ Pa = ρgh

⇒ Pa = 1.3 × 103 × 9.81 × 5 = 63765 Pa

**Hence the required pressure at the given depth is 63765 Pa**