Question

A team is to be selected from 13 players P1, P2, P3, P4, P5, P6, P7, P8, P9, P10, P11, P12 and P13. There will be seven players in the team. P2 cannot be selected with P1, P6 or P4. P7 cannot be selected with P2, P10, P11 or P13. If P8 and P13 both are selected, then P5 must be selected. P4 cannot be selected with P2, P10, P12 or P11. Which of the following is a correct selection of the team?   
1. P1, P3, P4, P5, P6, P8, P9
2. P1, P6, P11, P12, P13, P3, P4
3. P1, P3, P4, P5, P8, P9, P13
4. P2, P3, P5, P7, P8, P9, P13 

Answer 1

Correct Answer - Option 3 : P1, P3, P4, P5, P8, P9, P13

A team is to be selected from 13 players P1, P2, P3, P4, P5, P6, P7, P8, P9, P10, P11, P12 and P13.

1) P2 cannot be selected with P1, P6 or P4.

2) P7 cannot be selected with P2, P10, P11 or P13.

3) If P8 and P13 both are selected, then P5 must be selected.

4) P4 cannot be selected with P2, P10, PI2 or P11.

Option 1 - P1, P3, P4, P5, P6, P8, P9 in which P8 and P13 always with P5, So P13 not present with P8 and P5. So it is incorrect combination.

Option 2 - P1, P6, P11, P12, P13, P3, P4 in which P8 and P13 always with P5, so P5 and P8 not present and P4 cannot be selected with P11 and P12. So it is incorrect combination.

Option 3 - P1, P3, P4, P5, P8, P9, P13. follow all the condition. So it is correct combination. 

Option 4 - P2, P3, P5, P7, P8, P9, P13  in which P2 and P7 both together but in condition P2 and P7 never with same combination. So it is incorrect combination.

Hence, "option 3" is the correct answer.