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For maximum power to be transmitted by the belt, the maximum permissible tension in the belt is
1. equal to centrifugal tension
2. twice the centrifugal tension
3. thrice the centrifugal tension
4. four-times the centrifugal tension

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Correct Answer - Option 3 : thrice the centrifugal tension

Concept:

Centrifugal Tension (Tc):

  • Since the belt continuously runs over the pulleys, therefore some centrifugal force is caused, whose effect is to increase the tension on both the tight as well as the slack sides.
  • The tension caused by this centrifugal force is called centrifugal tension.
  • Condition for Maximum power transmitted by the belt is T = 3TC 
  • i.e. power transmitted will be maximum when tension is equal to three-time centrifugal tension or it shows that when the power transmitted is maximum, 1/3rd of the maximum tension is absorbed as centrifugal tension.

Power transmitted by a belt: 

P = (T1 – T2)v

For maximum power:

T1 = T/3

where T1 = Tension in the tight side, T = Maximum tension to which the belt is subjected.

The velocity of the belt for maximum power:

\(v = \sqrt {\frac{T}{{3m}}} \)

where m is mass of belt per unit length.

m = Area × length × density = b.t.l.ρ 

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