Data : L1 = 5m,
L2 = 6m,
l1 = 250 cm
E = \(\left(\cfrac{V}L \right)I\)
where V/L is the potential gradient and l is the balancing length.
∴ E1 = \(\left(\cfrac{V}{L_1 }\right)I_1\) = \(\left(\cfrac{V}{L_2 }\right)I_2\)
I2 = \(\left(\cfrac{L_2}{L_1}\right)\) x I1 = \(\cfrac65\) x 250 = 300 cm