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If the speed of the body is doubled and its mass gets half, then the kinetic energy of the body will be
1. Twice of initial
2. Half of initial
3. Remains same
4. Fours times of initial

1 Answer

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Correct Answer - Option 1 : Twice of initial

Concept:

Kinetic energy (KE): The energy possessed by a body due to the virtue of its motion is termed as kinetic energy. It is given by

\(KE = \frac{1}{2}m{v^2}\)

Where, m = Mass of the body, v = Velocity of the body

Calculation:

Given:

m2 = m1 / 2, v2 = 2v1

The initial kinetic energy of the body, \(KE_1 = \frac{1}{2}m_1{v_1^2}\)

Final kinetic energy of the body, \(KE_2 = \frac{1}{2}m_2{v_2^2}\)

\(KE_2 = \frac{1}{2}\frac {m_1}{2}{(2v_1)^2}\)

\(KE_2 = 2\times \frac{1}{2} {m_1}{v_1^2}\)

∴ K.E2 = 2 K.E1 

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