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Tap P can fill a cistern in 6 hours and tap Q can empty the full cistern in 10 hours. If both taps P and Q are kept open simultaneously, then in how many hours will the empty cistern be completely full ?
1. 15
2. 18
3. 12
4. 16

1 Answer

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Best answer
Correct Answer - Option 1 : 15

Given:

Tap P's 1 hour's work = 1/6

Tap Q's 1 hour's work = 1/10

Calculation:

Tap(P + Q)'s 1 hour's work = 1/6 - 1/10 = 4/60 = 1/15

∴ In 15 hours tank will be full.

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