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Amit alone can complete a piece of work in 15 days and Balbir alone can do the same work in 10 days.

If amit alone works for 3 days after which Balbir joins him, then the work will be finished in how many days?


1. \(4\frac{4}{5}\) days
2. \(\frac{1}{6}\) days
3. \(\frac{4}{5}\) days
4. \(7\frac{4}{5}\) days

1 Answer

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Best answer
Correct Answer - Option 4 : \(7\frac{4}{5}\) days

Given:

Work done by Amit = 15 days

Work done by Balbir = 10 days

Amit alone works = 3 days after Balbir joins him

Formula used:

Work done = Time × Efficiency

Calculation:

LCM of 15 and 10 = 30

Amit 1 day work = 30/15 = 2 units

Balbir 1 day work = 30/10 = 3 units

Amit alone work for 3 days = 2 × 3 = 6 days 

Remaining work = (30 –  6) = 24 days

Work done by Both = 24/(2 + 3)

⇒ 24/5 = \(4\frac{4}{5}\) days

Work will be finished by Amit and Balbir = (\(4\frac{4}{5}\) + 3) = \(7\frac{4}{5}\) days

∴ Required time to finished the work is \(7\frac{4}{5}\) days

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