Correct Answer - Option 3 : 1.55 gm/cc
Concept:
The fundamental relation between dry density (\({γ _d}\)), bulk density (γ) and water content (ω), is
\({γ _d}={γ\over{1+w}}\)
Calculation:
Given,
γ = 1.769 gm/cc, w = 13.9%
\({γ _d} = \;\frac{1.769}{{1 + 0.139}}\)
\({γ _d} = \frac{{1.769}}{{1.139}} = 1.55\;gm/cc\)