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A heap of wheat is in the form of a cone whose base diameter is 8.4 m and height is 1.75 m. The heap is to be covered by canvass. What is the area (in m2) of the canvas required? (Use \(\pi=\frac{22}{7}\))
1. 60.06
2. 115.5
3. 60.6
4. 115.05

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Correct Answer - Option 1 : 60.06

Given:

Diameter of cone = 8.4m

Height of cone = 1.75m

Formula:

Curved surface area of cone = πrl

Calculation:

Radius of cone = 8.4/2 = 4.2 m

(Slant height)2 = radius2 + height2

(slant height)2 = 4.22 + 1.752 = 20.7025

Slant height = 4.55 m

Curved surface area of cone = πrl

= 22/7 × 4.2 × 4.55

= 60.06

∴ Area of canvas required is 60.06 m2.

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