Question

In a multiple-choice question there are four alternative answers, of which one or more are correct. A candidate will get marks in the question only if he ticks the correct answers. The candidates decide to tick the answers at random, if he is allowed upto three chances to answer the questions, find the probability that he will get marks in the question.

Answer 1

The total number of ways to answer the question = ⁴c₁ + ⁴c₂+ ⁴c₃ + ⁴c₄ = 24 - 1 =15.

P(getting marks) = P( correct answer in I chance) + P(correct answer in II chance) + P(correct answer in III chance)

= 1/15 + (14/15.1/14) + (14/15.13/14.1/13)

= 3/15 = 1/5