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If the nine-digit number 23541y49x is divisible by 72, then (3x + 5y) ∶ (5x + 3y) is equal to:
1. 7 ∶ 9
2. 4 ∶ 3
3. 9 ∶ 7
4. 3 ∶ 4

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Correct Answer - Option 1 : 7 ∶ 9

Concept:

Divisibility by 9 = When the sum of the digits of a number is divisible by 9, the number is said to be divisible by 9.

Divisibility by 8 = When the last 3 digits of a number are divisible by 8, the number is said to be divisible by 8.

Given: 

23541y49x is divisible by 72

Calculation:

23541y49x is divisible by 72, which is the product of 8 and 9, which are two co-prime. So the number has to be divisible by both 8 and 9. 

23541y49x is divisible by 8, if 49x is divisible by 8, which gives x = 6.

The number becomes 23541y496, which will be divisible by 9, if the sum of the digits becomes divisible by 9. 

Now, 2 + 3 + 5 + 4 + 1 + y + 4 + 9 + 6 = 34 + y 

⇒ y should be 2, so that the digit sum becomes (34 + 2 = 36) which is divisible by 9. 

For x = 6, y = 2

(3x + 5y) ∶ (5x + 3y) 

⇒ (3 × 6 + 5 × 2) : (5 × 6 + 3 × 2)

⇒ (18 + 10) : (30 + 6)

⇒ 28 : 36 

⇒ 7 : 9 

∴ The required result = 7 : 9  

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