Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
185 views
in Statistics by (108k points)
closed by
The mean of a table is 20 and standard deviation is 5, then its coefficient of variation is :
1. 20%
2. 2%
3. 25%
4. 5%

1 Answer

0 votes
by (111k points)
selected by
 
Best answer
Correct Answer - Option 3 : 25%

Concept:

The coefficient of variation can be calculated as:

\({\rm{Coefficient\;of\;variation}} = {\rm{}}\frac{{{\rm{standard\;deviaiton}}}}{{{\rm{Mean}}}} \times 100\)

Calculation:

Given:

Mean = 20 and Standard deviation = 5

As we know, 

\({\rm{Coefficient\;of\;variation}} = {\rm{}}\frac{{{\rm{standard\;deviaiton}}}}{{{\rm{Mean}}}} \times 100\)

\(\Rightarrow {\rm{Coefficient\;of\;variation}} = {\rm{}}\frac{5}{20} \times 100 = 25\%\)

Adding a constant to each value:  The median, mean, and quartiles will be changed by adding a constant to each value. However, the range, interquartile range, standard deviation and variance will remain the same.

Multiplying every value by a constant: however, will multiply the mean, median, quartiles, range, interquartile range, and standard deviation by that constant, and multiply the variance by the square of that constant.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...