Correct Answer - Option 4 : Saturday
Given: 12 October 1997 was a Saturday.
Number of leap years = 3 (2000, 2004, 2008)
Therefore, number of odd days = 3 × 2 = 6
Non leap years = 8 (1998, 1999, 2001, 2002, 2003, 2005, 2006, and 2007)
Therefore, number of odd days = 8 × 1 = 8
Total odd days = 6 + 8
= 14
Now, 14 ÷ 7 = 2
⇒ No remainder.
⇒ 12 October 2008 will be the same day as on 12 October 1997.
Hence, Saturday is the correct answer.
