# How many sleepers will be required for 1280 meter long broad gauge track? Take the sleeper density as M+5 and the length of the rail as 12.8 m. (All t

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How many sleepers will be required for 1280 meter long broad gauge track? Take the sleeper density as M+5 and the length of the rail as 12.8 m. (All terms are used in their normal sense)
1. 1800
2. 1000
3. 1200
4. 1500

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Correct Answer - Option 1 : 1800

Explanation

Sleeper density means number of rails per rail length and it is represented by M + x ;

where 'M' is the rail length and 'x' is any integer that varies from 3 to 7.

Given:

Sleeper Density = M + 5

No of sleepers in 12.8 m rail length   = 12.8 + 5 = 17.8 ≈ 18 sleepers.

So, the total number of sleepers (T) is given by

${\rm{T}} = {\rm{}}\frac{{{\rm{Total\;rail\;length}}\; \times \;{\rm{No\;of\;sleeper\;per\;unit\;rail\;length}}}}{{{\rm{rail\;length}}}}$

${\bf{T}} = \frac{{1280\; \times \;18}}{{12.8}}$ = 1800