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A projectile can have the same range R for two angles of projection. If t1 and t2 be the time of flights in the two cases, then the product of the two time of flights is proportional to
1. \(\frac{1}{R}\)
2. R
3. R2
4. \(\frac{1}{R^2}\)

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Correct Answer - Option 2 : R

The correct answer is R.

  • Range is same for angles of projection θ and (90-θ)
    • ​t1= 2usinθ/g
    • t2= [2u sin(90-θ)]/g = 2u cosθ/g.
    • hence t1t2= 4(u2 sinθcosθ/g2) = 2/g[u2sinθ/g]
    • =(2/g)R, where R is range.
    • hence,t1t2 is directly proportional to R because R is constant.

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