Correct Answer - Option 3 : A-2, B-1, C-4, D-3
Concept:
(i) Average Daily Demand (q)
Average daily demand = (per capita average consumption in litre/person/day) × population
(ii) Maximum Daily Demand
Maximum daily demand = 1.8 × Avg. daily demand = 1.8 × q
(iii) Maximum Hourly Demand:
Maximum hourly demand of the maximum day i.e. Peak demand
= 1.5 × Avg hourly demand of the maximum day \(= 1.5 × \left[ {1.8 × \frac{q}{{24}}} \right] = 2.7\left[ {\frac{q}{{24}}} \right]\)= 2.7 × annual avg hourly demand
(iv) Monthly peak demand = 1.28 × monthly average demand
(v) Yearly peak = 1.0 × yearly average demand
The percentage ratio of maximum demand to the average demand can be computed using Good Rich equation;
p = 180 × t-0.10
where
t = time(days)
Demand |
Fluctuation |
Hourly |
2.7 |
Daily |
1.8 |
Weekly |
1.48 |
Monthly |
1.28 |
Yearly |
1 |
Fluctuation in hourly demand is also termed as Peak factor which depends upon the population as follows;
Population |
Peak factor |
< 50000 |
3 |
50000 - 200000 |
2.5 |
> 200000 |
2 |