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A mixture contains acid and alcohol in the ratio of 3 : 2. On adding 10 litres of alcohol in mixture, the ratio of acid to alcohol becomes 3 : 5. The quantity of acid (in litres) in the original mixture was:
1. 5
2. 4.5
3. 5.5
4. 10

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Correct Answer - Option 4 : 10

Given:

Mixture of acid and alcohol in the ratio = 3 : 2

Alcohol adding in the mixture = 10 litres

After adding water the ratio of mixture = 3 : 5

Calculation:

Let acid and alcohol in the mixture be 3x and 2x respectively

According to question

⇒ 3x/(2x + 10) = 3/5

⇒ 15x = 6x + 30

⇒ 9x = 30

⇒ x = 10/3

The quantity of acid in the mixture = 10/3 × 3

⇒ 10

∴ The quantity of acid in the original solution is 10.

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