Question

In a mixture of liquid 1/5, part is acid 2/5 part is alcohol and the remaining part is water. If the total quantity of the mixture is 20 litres, then how much water (in litre) does the mixture contain?
1. 12
2. 8
3. 15
4. 4

Answer 1

Correct Answer - Option 2 : 8

Given:

Part of liquid in mixture = 1/5

Part of acid in mixture = 2/5

Total quantity of mixture = 20 litres

Calculation:

According to question

Remaining part of water = 1 – (1/5 + 2/5)

⇒ 1 – 3/5

⇒ 2/5

Now,

Mixture contain water = Total quantity of mixture/Remaining part of water

⇒ (20 × 2/5) litres

⇒ 8 litres

∴ Required mixture contain water is 8