Correct Answer  Option 1 : 0.3
Calculation
The coefficient of rank correlation = 1 – 6∑d^{2}/n(n^{2} – 1)
D = r_{1} – r_{2}
r_{1}, r_{2}  are ranks
Mathematics (r_{1})

Statistics (r_{2})

d = Ir_{1} – r_{2}I

d^{2}

3

6

3

9

5

4

1

1

8

9

1

1

4

8

4

16

7

1

6

36

10

2

8

84

2

3

1

1

1

10

9

81

6

5

1

1

9

7

2

4

Total

10


∑d^{2} = 214

According to spearman’s rank correlation coefficient ρ = 1 – 6∑d^{2}/n(n^{2} – 1)
⇒ 1 – 6 × 214/10(100 – 1)
⇒ 1 – 6 × 214/990
⇒ 1 – 1.297
∴ The value of rank correlation is approx. – 0.3