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In amplitude shift keying, transmission bandwidth is equal to
1. Base bandwidth
2. Twice base bandwidth
3. Half the base bandwidth
4. Four times base bandwidth

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Correct Answer - Option 1 : Base bandwidth

In amplitude shift keying, transmission bandwidth is equal to Base bandwidth. 

The bandwith of differnet passband modulation scheme is as shown:

Modulation Scheme

Bandwidth

ASK and PSK

2Rb

(Same as baseband BW)

FSK

fH - fL + 2Rb

where fH is the higher cut-off frequency, fL is the lower cut-off frequency.

DSB-FC & DSB-SC

2fm

Where fm is the frequency of the message signal.

SSB-SC

fm

VSB-SC

fm + fv

where fv is the vestige frequency

NBFM (β < 1)

2fm

WBFM (β < 1)

2fm(1 + βf)

Where βf is the modulation index of WBFM, given by βf = Δf/fm,  where Δf is the frequency deviation.

PM

2fm(1 + βp)

Where βp is the modulation index of pm, given by βp = Kp × Am, where Kp is amplitude sensitivity of PM signal, Am is the amplitude of message signal.

M - array PSK

2Rb/n

Where n is the number of bits.

M – array QAM

For rectangular pulse, 2Rb/n

For raised cosine signal, Rb(1 + α)/n,

where α is the roll-off.

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