Correct Answer - Option 3 : Rs. 7,290

**Given:**

Diameter of the cylindrical vessel = 54 cm

Height of the cylindrical vessel = 54 cm

Radius of the cylindrical glass = 3 cm

Height of the cylindrical glass = 9 cm

Selling Price of one glass of Sharbat = Rs. 15

**Formula Used:**

Volume of the Cylinder = πr^{2}h

where,

r = Radius of the cylinder

h = Height of the cylinder

**Calculation:**

Let the radius and height of the cylindrical vessel be 'R' and 'H' respectively.

And let the radius and height of the cylindrical glass be 'r' and 'h' respectively.

According to the question,

R = Diameter/2

⇒ 54/2

⇒ 27 cm

Now, Number of glasses of Sharbat sold in a day = (Volume of the cylindrical vessel)/(Volume of the cylindrical glass)

\(⇒ \frac{πR^2H}{πr^2h}\)

\(⇒ \frac{R^2H}{r^2h}\)

\(⇒ \frac{[(27)^2 × 54]}{[3^2 × 9]}
\)

⇒ 9 × 9 × 6

⇒ 81 × 6

⇒ 486 glasses

So, Total money earned by the Sharbat maker at the end of the day = Number of glasses × Selling price of one glass of Sharbat

⇒ 486 × 15

⇒ 7,290

**∴ The total money earned by the Sharbat maker at the end of the day Rs. 7,290.**