Correct Answer - Option 2 : 576π cm
2
Given:
The radius of 3 small spherical ball = 6 cm, 8 cm and 10 cm
Concept used:
The volume of 3 spherical melted balls = Volume of 1 big spherical ball
Formula used:
The volume of sphere = (4/3) × π × r3
where,
r → Radius of the sphere
The volume of big sphere = (The volume of the first sphere + The volume of the second sphere + The volume of the third sphere)
Calculations:
According to the question, we have
The volume of sphere = (4/3) × π × r3
The volume of the big ball = {(4/3) × π × (6)3} + {(4/3) × π × (8)3} + {(4/3) × π × (10)3}
⇒ (4/3) × π × r3 = (4/3) × π × (216 + 512 + 1000)
⇒ r3 = 1728
⇒ r = 12
Now,
The total surface area of the big spherical ball = 4πr2
⇒ 4π × (12)2
⇒ 4π × 144
⇒ 576π
∴ The total surface area of the big spherical ball is 576π cm2.