Correct Answer - Option 2 : 10 min
Given:
A pipe of diameter d can empty the tank in 40 minutes
Formula used:
Area of a circle = πr2
Work done = Time × Efficiency
Calculation:
Total work done by the pipe with the diameter d
40 × π(d/2)2 = 10πd2
Now the diameter is doubled
So the time to empty the tank is
Time = \(\dfrac{10πd^2}{\pi (\frac{2d}{2})^2}\)
⇒ Time = 10 minutes
∴ The pipe with double the diameter will empty the tank in 10 minutes.